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  Visual Basic    (Arquivos/Diretórios)

Título da Dica:  Abrindo a caixa de dialogo 'ABRIR' do Windows via API
Postada em 3/2/2003 por Felipe            
API:
Private Type OPENFILENAME
    lStructSize As Long
    hwndOwner As Long
    hInstance As Long
    lpstrFilter As String
    lpstrCustomFilter As String
    nMaxCustFilter As Long
    nFilterIndex As Long
    lpstrFile As String
    nMaxFile As Long
    lpstrFileTitle As String
    nMaxFileTitle As Long
    lpstrInitialDir As String
    lpstrTitle As String
    flags As Long
    nFileOffset As Integer
    nFileExtension As Integer
    lpstrDefExt As String
    lCustData As Long
    lpfnHook As Long
    lpTemplateName As String
End Type

Private Declare Function GetOpenFileName Lib "comdlg32.dll" Alias "GetOpenFileNameA" (pOpenfilename As OPENFILENAME) As Long

CODIGO:
Dim ofn As OPENFILENAME
    ofn.lStructSize = Len(ofn)
    ofn.hwndOwner = Form1.hWnd
    ofn.hInstance = App.hInstance
    ofn.lpstrFilter = "Text Files (*.txt)" + Chr$(0) + "*.txt" + Chr$(0) + "Rich Text Files (*.rtf)" + Chr$(0) + "*.rtf" + Chr$(0)
        ofn.lpstrFile = Space$(254)
        ofn.nMaxFile = 255
        ofn.lpstrFileTitle = Space$(254)
        ofn.nMaxFileTitle = 255
        ofn.lpstrInitialDir = curdir
        ofn.lpstrTitle = "Our File Open Title"
        ofn.flags = 0
        Dim a
        a = GetOpenFileName(ofn)

        If (a) Then
                MsgBox "File to Open: " + Trim$(ofn.lpstrFile)
        Else
                MsgBox "Cancel was pressed"
        End If

altere conforme necessidades.
 


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